Q133 / 155 · WBJEE 2024 · Physics

In a single-slit diffraction experiment, the slit is illuminated by light of two wavelength $\lambda_1$ and $\lambda_2$. It is observed that the 2 nd order diffraction minimum for $\lambda_1$ coincides with the 3 rd diffraction minimum for $\lambda_2$. Then

  • A
    $\frac{\lambda_1}{\lambda_2}=\frac{2}{3}$
  • B
    $\frac{\lambda_1}{\lambda_2}=\frac{5}{7}$
  • Correct answer
    C
    $\frac{\lambda_1}{\lambda_2}=\frac{3}{2}$
  • D
    $\frac{\lambda_1}{\lambda_2}=\frac{7}{5}$

Solution

Hint: $d \sin \theta=\mathrm{n} \lambda$ $$ \begin{aligned} & \mathrm{n}_1 \lambda_1=\mathrm{n}_2 \lambda_2 \\ & \frac{\lambda_1}{\lambda_2}=\frac{\mathrm{n}_2}{\mathrm{n}_1}=3 / 2 \end{aligned} $$

Hence, the correct answer is option: 'C'.

More Wave Optics Questions