Q239 / 270 · NDA 2013 (Phase 2) · Mathematics

In a relay race, there are six teams $\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}, \mathrm{E}$ and F. What is the probability that $\mathrm{A}, \mathrm{B}, \mathrm{C}$ finish first, second, third respectively?

  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{12}$
  • C
    $\frac{1}{60}$
  • Correct answer
    D
    $\frac{1}{120}$

Solution

Probability that A comes first $=\frac{1}{6}$ Probability that $B$ comes second $=\frac{1}{5}$ Probability that C comes third $=\frac{1}{4}$ Required probability $=\frac{1}{6} \times \frac{1}{5} \times \frac{1}{4}=\frac{1}{120}$

Hence, the correct answer is option: 'D'.

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