Q108 / 125 · BITSAT 2012 · Physics

In a region of space having a uniform electric field $\mathrm{E}$, a hemispherical bowl of radius $\mathrm{r}$ is placed. The electric flux $\phi$ through the bowl is

  • A
    $2 \pi \mathrm{RE}$
  • B
    $4 \pi R^{2} E$
  • Correct answer
    C
    $2 \pi R^{2} E$
  • D
    $\pi R^{2} E$

Solution

$\phi=\mathrm{E}(\mathrm{ds}) \cos \theta=\mathrm{E}\left(2 \pi \mathrm{r}^{2}\right) \cos 0^{\circ}=2 \pi \mathrm{r}^{2} \mathrm{E}$

Hence, the correct answer is option: 'C'.

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