In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0\times {10}^{10} \mathrm{Hz}$ and amplitude $48 \mathrm{V} {\mathrm{m}}^{-1}$. Then the amplitude of oscillating magnetic field is: (Speed of light in free space =$3\times {10}^8 \mathrm{m} {\mathrm{s}}^{-1}$)

• A

  $1.6\times {10}^{-6} \mathrm{T}$
• B

  $1.6\times {10}^{-9} \mathrm{T}$
• C

  $1.6\times {10}^{-8} \mathrm{T}$
• Correct answer
  D

  $1.6\times {10}^{-7} \mathrm{T}$

Hence, the correct answer is option: 'D'.