Q47 / 56 · KVPY 2018 (SA) · Physics

In a particle accelerator, a current of 500 μA is carried by a proton beam in which each proton has a speed of 3×107 m/s. The cross-sectional area of the beam is 1.50 mm2. The charge density in this beam (in C/m3 is close to
 

  • A
    10-8
  • B
    10-7
  • C
    10-6
  • Correct answer
    D
    10-5

Solution

If Q is charge contained in L

length of beam of area A, then

L×A×ρ=Q

where, ρ= charge density of beam.

 

So,  ρ=QL×A=Q/tL/t×A=Iv×A

 

=500×10-63×107×1.50×10-6

 

=53×1.5×10-5=11×10-5 Cm-3

 

Hence, the correct answer is option: 'D'.

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