Q44 / 97 · NTA Abhyas (JEE Main) 2020 · Physics · Nuclear Physics

In a nuclear fission, when a mass of $0.5 g$ of uranium is consumed, the energy obtained in $kWh$ is $n \times 10^{7}$ . Find the value of $n$ .

Correct answer: 1.25

Solution

E = Δ m c^{2}

= 0.5 \times 10^{- 3} \times {(3 \times 10^{8})}^{2}

= 4.5 \times 10^{13}

E = \frac{4.5 \times 10^{13}}{3.6 \times 10^{6}}

= 1.25 \times 10^{7} kWh

Hence, the correct answer is 1.25.

More Nuclear Physics Questions

The energy spectrum of β - p a r t i c l e s [number N E as a function of β - energy E ] emitted from a radioactive source is
In a sample initially, there are an equal number of atoms of two radioactive isotopes A and B . 3 days later, the number of atoms of A is tw
A and B are two radioactive substances whose half-lives are 1 and 2 years respectively. Initially, 10 g of A and, 1 g of B is taken. The tim
Some amount of a radioactive substance (half-life = 10 days) is spread inside a room and consequently, the level of radiation becomes 50 tim
A nucleus of mass 20 u emits a γ -photon of 6 M e V . If the emission assume to occur when nucleus is free and rest, then the nucleus will h
How long will a radioactive isotope, whose half-life is T years, take for its activity to reduce to 1 8 th of its initial value?