Q7 / 75 · JEE Main 2025 (28 Jan Shift 1) · Chemistry
In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields?
A. $\mathrm{n}=1, \mathrm{l}=0, \mathrm{~m}_1=0$
B. $\mathrm{n}=2, \mathrm{l}=0, \mathrm{~m}_1=0$
C. $\mathrm{n}=2, \mathrm{l}=1, \mathrm{~m}_1=1$
D. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=1$
E. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=0$
Choose the correct answer from the options given below:
- AB and C Only
- BA and B Only
- CC and D Only
- Correct answerDD and E Only
Solution
$\begin{array}{lc} \mathrm{A}: \mathrm{n}=1, \ell=0, \mathrm{~m}_{\ell}=0 & 1 \mathrm{~s} \\ \mathrm{B}: \mathrm{n}=2, \ell=0, \mathrm{~m}_{\ell}=0 & 2 \mathrm{~s} \\ \mathrm{C}: \mathrm{n}=3, \ell=1, \mathrm{~m}_{\ell}=1 & 3 \mathrm{p} \\ \mathrm{D}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=1 & 3 \mathrm{~d} \\ \mathrm{E}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=0 & 3 \mathrm{~d} \\ \end{array}$
In absence of electric and magnetic fields, all orbitals of 3d are degenerate
Hence, the correct answer is option: 'D'.