Q32 / 225 · JEE Main 2002 · Chemistry

In a hydrogen atom, if energy of an electron in ground state is 13.6 eV, then that in the 2nd excited state is

  • Correct answer
    A
    1.51 eV
  • B
    3.4 eV
  • C
    6.04 eV
  • D
    13.6 eV

Solution

$2^{\text {nd }}$ excited state will be the 3 rd energy level $$ \mathrm{E}_{\mathrm{n}}=\frac{13.6}{\mathrm{n}^2} \mathrm{eV} \text { or } \mathrm{E}=\frac{13.6}{9} \mathrm{eV}=1.51 \mathrm{eV} $$

Hence, the correct answer is option: 'A'.

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