Q142 / 160 · AP EAMCET 2021 (23 Aug Shift 2) · Physics

In a given process, for an ideal gas, $\Delta W=0$ and $\Delta Q < 0$. Then, for the gas,

  • Correct answer
    A
    the temperature will decrease
  • B
    the volume will increase
  • C
    the pressure will remain constant
  • D
    the temperature will increase

Solution

In the given process, for an ideal gas $\Delta W=0$ and $\Delta Q < 0$ By lst law of thermodynamics, $\Delta Q=\Delta W+\Delta U$ where, $\Delta U=$ internal energy of gas. $\begin{aligned} & \Rightarrow \quad \Delta Q=\Delta U \\ & \text { and also } \Delta U < 0 .\end{aligned}$ As the internal energy depends on temperature. Therefore, if change in internal energy is negative, it mean temperature of gas is decreased.

Hence, the correct answer is option: 'A'.

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