Q76 / 160 · AP EAMCET 2023 (15 May Shift 1) · Mathematics

In a game, a pair of dice is rolled 24 times. If a person wins the game by not getting 6 on both the dice in any one of the 24 rolls, then the probability that a person wins the game is

  • Correct answer
    A
    $\left(\frac{35}{36}\right)^{24}$
  • B
    $\left(\frac{17}{18}\right)^{24}$
  • C
    $\left(\frac{11}{12}\right)^{24}$
  • D
    $\left(\frac{5}{6}\right)^{24}$

Solution

No. of events in sample space when a pair of dice is rolled 24 times $=(6 \times 6)^{24}=(36)^{24}$. No. of event of not getting on both of the dice $=36$ $\therefore$ The required probability is $=\frac{(35)^{24}}{(36)^{24}}$

Hence, the correct answer is option: 'A'.

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