Q13 / 180 · COMEDK 2019 · Chemistry

In a first order reaction, molar concentration of a reactant decreases from $0.1$ to $0.01$ in $100 \mathrm{~s}$. The rate constant of the reaction is

  • A
    $2.3030$
  • Correct answer
    B
    $0.02303$
  • C
    $0.2303$
  • D
    $0.002303$

Solution

$\left[A_{0}\right]=0.1$ $$ \begin{aligned} {\left[A_{t}\right] } &=0.01 \\ t &=100 \mathrm{~s} \end{aligned} $$ 1st order reaction, $$ \begin{aligned} k &=\frac{2303}{t} \log \frac{\left[A_{0}\right]}{\left[A_{t}\right]} \\ &=\frac{2303}{100} \log \frac{0.1}{0.01}=0.02303 \mathrm{~s}^{-1} \end{aligned} $$

Hence, the correct answer is option: 'B'.

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