In a communication system operating at wavelength $800 nm,$ only one percent of source frequency is available as signal bandwidth. The number of channels accommodated for transmitting $TV$ signals of band width $6 MHz$ are (Take velocity of light )

• Correct answer
  A

  $6.25\times {10}^5$
• B

  $4.87\times {10}^5$
• C

  $3.75\times {10}^6$
• D

  $3.86\times {10}^6$

Hence, the correct answer is option: 'A'.