Q34 / 88 · NTA Abhyas (JEE Main) 2020 · Physics · Semiconductors

In a common-emitter configuration of a transistor, the base current $I_{E} = 2 μ A$ , $α = 0.9$ then the value of $I_{C}$ is

A
$3.0 μ A$
B
$2.25 μ A$
C
$4.9 μ A$
Correct answer
D
$1.8 μ A$

Solution

We know that current gain is given by,

α = \frac{I_{c}}{I_{b}}

∴

I_{c} = α \times I_{b} = 0.9 \times 2 = 1.8 μ A

Hence, the correct answer is option: 'D'.

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