In a collinear collision, a particle with an initial speed v_0 strikes a stationary particle of the same mass. If the final total kinetic energy is…

Question

In a collinear collision, a particle with an initial speed v_0 strikes a stationary particle of the same mass. If the final total kinetic energy is 50% greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after the collision, is

MARKS Content Team · Accepted Answer

Correct answer: (C) √( 2) v_0. KE_2=3/2mv02. Conservation of momentum, v_1 +v_2 =v_0 . Conservation of energy, 1/2mv12+1/2mv22=1/2 × 3/2mv02 ⇒v12+v22=3/2v02⇒v12+v22+2v_1v_2=v02⇒3/2v02+2v_1v_2=v02 ⇒2v_1v_2=−1/2v02⇒(v1−v2)^2=3/2v02+1/2v02 =2 v 0 2 ⇒v_1−v_2=√2v_0.

In a collinear collision, a particle with an initial speed $v_{0}$ strikes a stationary particle of the same mass. If the final total kinetic energy is $50 %$ greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after the collision, is

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Relevant Questions

In a collinear collision, a particle with an initial speed v0 strikes a stationary particle of the same mass. If the final total kinetic energy is 50% greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after the collision, is

Solution

Relevant Questions

In a collinear collision, a particle with an initial speed $v_{0}$ strikes a stationary particle of the same mass. If the final total kinetic energy is $50 %$ greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after the collision, is