Imagine that a reactor converts all the given mass into energy and that it operates at a power level of 10^9 Watt . The mass of the fuel consumed per…

Question

Imagine that a reactor converts all the given mass into energy and that it operates at a power level of

10^{9} Watt

. The mass of the fuel consumed

per hour

, in the reactor, will be:
(velocity of light,

c

is

3 \times 10^{8} m s^{- 1}

)

MARKS Content Team · Accepted Answer

Correct answer: (C) 4×10^(-2 )g. Power of reactor, P=E/(Δt)=(Δmc^2)/(Δt)(From mass-energy equivalence equation) Given in the problem power level =10^9 Watt . (∆m)/(∆t)=P/(c^2) =(10^9)/(3×10^82) ⇒ (∆m)/(∆t)=(10^(-7))/9 kg s^(-1) The mass of fuel consumed per hour=(10^(-7))/9×1000 g3600 h^(-1)=4×10^(-2 )g h^(-1).

Imagine that a reactor converts all the given mass into energy and that it operates at a power level of $10^{9} Watt$ . The mass of the fuel consumed $per hour$ , in the reactor, will be:
(velocity of light, $c$ is $3 \times 10^{8} m s^{- 1}$ )

Solution

Relevant Questions

Imagine that a reactor converts all the given mass into energy and that it operates at a power level of 109 Watt . The mass of the fuel consumed per hour, in the reactor, will be:(velocity of light, c is 3×108 m s-1)

Solution

Relevant Questions

Imagine that a reactor converts all the given mass into energy and that it operates at a power level of $10^{9} Watt$ . The mass of the fuel consumed $per hour$ , in the reactor, will be:
(velocity of light, $c$ is $3 \times 10^{8} m s^{- 1}$ )