Q42 / 125 · BITSAT 2017 · Mathematics

If z=a+ib satisfies arg(z-1)=arg(z+3i), then (a-1):b=

  • A
    2:1
  • Correct answer
    B
    1:3
  • C
    -1:3
  • D
    None of these

Solution

We have,

arg(z-1)=arg(z+3i)

⇒arg((a-1)+ib)=arg(a+(b+3)i)

⇒tan-1ba-1=tan-1b+3a

⇒ ba-1=b+3a

⇒ ab=(a-1)(b+3)

⇒ 3(a-1)=b

⇒ (a-1):b=1:3

Hence, the correct answer is option: 'B'.

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