Q51 / 155 · WBJEE 2023 · Mathematics
If \(y=\frac{x}{\log _e|c x|}\) is the solution of the differential equation \(\frac{d y}{d x}=\frac{y}{x}+\phi\left(\frac{x}{y}\right)\), then \(\phi\left(\frac{x}{y}\right)\) is given by
- A\(\frac{y^2}{x^2}\)
- Correct answerB\(-\frac{y^2}{x^2}\)
- C\(\frac{x^2}{y^2}\)
- D\(-\frac{x^2}{y^2}\)
Solution
Hint : \(y=\frac{x}{\ell n|c x|}\)
\(\begin{aligned}
& \frac{\mathrm{dy}}{\mathrm{dx}}=\frac{\ell \mathrm{n}|c x|-1}{(\ell \mathrm{n}|\mathrm{cx}|)^2}=\frac{1}{\ell \mathrm{n}|\mathrm{cx}|}-\frac{1}{(\ell \mathrm{n}|\mathrm{cx}|)^2} \\
& \Rightarrow \frac{\mathrm{dy}}{\mathrm{dx}}=\frac{\mathrm{y}}{\mathrm{x}}-\left(\frac{\mathrm{y}}{\mathrm{x}}\right)^2 \quad \therefore \phi\left(\frac{\mathrm{x}}{\mathrm{y}}\right)=-\frac{\mathrm{y}^2}{\mathrm{x}^2}
\end{aligned}\)
Hence, the correct answer is option: 'B'.