If y=tan^(-1)secx-tanx, then the value of dy/dx is

Question

MARKS Content Team · Accepted Answer

Correct answer: -0.5. y=tan^(-1)secx-tanx y=tan^(-1)(1-sinx)/cosx ⇒y=tan^(-1)(cosx^(2-sinx22))/(cos^2x2)-sin^2x/2 ⇒y=tan^(-1)cosx/2-sinx/2cosx/2+sinx/2 ⇒y=tan^(-1)(1-tanx)/21+tanx/2 ⇒y=tan^(-1)tan(π)/4-x/2 ⇒y=(π)/4-x/2 Differentiating with respect to x, we get ⇒dy/dx=(-1)/2=-0.5

If $y = {t a n}^{- 1} (s e c x - t a n x),$ then the value of $\frac{d y}{d x}$ is

Solution

More Differentiation Questions

If y=tan-1secx-tanx, then the value of dydx is

Solution

More Differentiation Questions

If $y = {t a n}^{- 1} (s e c x - t a n x),$ then the value of $\frac{d y}{d x}$ is