If $y=\frac{\mathrm{l}\mathrm{n}\mathrm{}x}{x}$, then $\frac{d^{2}y}{d{x}^2}=\frac{\mathrm{}\overline{)2}\mathrm{}}{x^3}\left(\mathrm{l}\mathrm{n}x-\lambda \right)$, where $\lambda$ is

• Correct answer
  A

  $\frac{3}{2}$
• B

  $\frac{2}{3}$
• C

  $\frac{1}{2}$
• D

  $\frac{1}{3}$

Hence, the correct answer is option: 'A'.