Q29 / 46 · NTA Abhyas (JEE Main) 2020 · Mathematics · Differentiation

If y=cos⁡xcos⁡2xcos⁡4xcos⁡8x, then dydx at x=π2 is

  • Correct answer
    A
    1
  • B
    0
  • C
    4
  • D
    16

Solution

y=sin⁡16x16sin⁡x  ∵ cos⁡Acos⁡2A.........cos⁡2n-1A=sin2nA2nsin⁡A
So, dydx=116sin⁡x⋅16cos⁡16x-sin⁡16xcos⁡xsin⁡x2
Putting x=π2, we get, 
dydx=116⋅1.161-012=1

Hence, the correct answer is option: 'A'.

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