If y=2 x^3-2 x^2+3 x-5 , then for x=2 and Δ x=0.1 value of Δ y is

Correct answer: (B) 1.9. Hints: dy/dx=6 x^2-4 x+3 Δ y= (dy/dx )_x-2 Δ x=1.9

Q65 / 160 · WBJEE 2011 · Mathematics

If \(y=2 x^3-2 x^2+3 x-5\), then for \(x=2\) and \(\Delta x=0.1\) value of \(\Delta y\) is

A
2.002
Correct answer
B
1.9
C
0
D
09

Solution

\(\text { Hints: } \frac{\mathrm{dy}}{\mathrm{dx}}=6 \mathrm{x}^2-4 \mathrm{x}+3 \quad \Delta \mathrm{y}=\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)_{\mathrm{x}-2} \Delta \mathrm{x}=1.9\)

Hence, the correct answer is option: 'B'.

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