If ϕx=log_8⁡log_3⁡x, then ϕ^(′) e is equal to

Question

MARKS Content Team · Accepted Answer

Correct answer: (C) 1/(elog⁡8). We have, ϕx=log_8⁡log_3⁡x=log_8⁡(log⁡x)/(log⁡3) =log_8⁡log⁡x-log_8⁡log⁡3 =(log⁡log⁡x)/(log⁡8)-log_8⁡log⁡3 ϕ^(′) x =1/log8 ⋅1/logx ⋅1/x −0 ∴ϕ^(′) e =1/log8 ⋅1/loge ⋅1/e =1/elog8

If $ϕ (x) = \log_{8} \log_{3} x,$ then $ϕ^{'} (e)$ is equal to

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More Differentiation Questions

If ϕx=log8⁡log3⁡x, then ϕ ′ e is equal to

Solution

More Differentiation Questions

If $ϕ (x) = \log_{8} \log_{3} x,$ then $ϕ^{'} (e)$ is equal to