Q80 / 160 · AP EAMCET 2025 (24 MAY SHIFT 1) · Mathematics

If X is a binomial variate with mean $\frac{16}{5}$ and variance $\frac{48}{25}$, then $\mathrm{P}(\mathrm{X} \leq 2)=$

  • Correct answer
    A
    $\frac{3^6(169)}{5^8}$
  • B
    $\frac{3^7(71)}{5^8}$
  • C
    $\frac{3^8}{(43) 5^8}$
  • D
    $\frac{3^6(158)}{5^8}$

Hence, the correct answer is option: 'A'.

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