Q80 / 160 · AP EAMCET 2025 (24 MAY SHIFT 1) · Mathematics
If X is a binomial variate with mean $\frac{16}{5}$ and variance $\frac{48}{25}$, then $\mathrm{P}(\mathrm{X} \leq 2)=$
- Correct answerA$\frac{3^6(169)}{5^8}$
- B$\frac{3^7(71)}{5^8}$
- C$\frac{3^8}{(43) 5^8}$
- D$\frac{3^6(158)}{5^8}$
Hence, the correct answer is option: 'A'.