If x→ and y→ be two non-collinear vectors and a triangle ABC with side lengths a,b,c satisfy the vector equation 20a-15bx→+15b-12cy→+12c-20ax→×y→=0→…

Question

If x→ and y→ be two non-collinear vectors and a triangle ABC with side lengths a,b,c satisfy the vector equation 20a-15bx→+15b-12cy→+12c-20ax→×y→=0→, then ∆ABC is

MARKS Content Team · Accepted Answer

Correct answer: (C) a right angle triangle. ∵x→,y→ and x→×y→ are non coplanar vectors 20a-15b=0,15b-12c=0,12c-20a=0 ⇒a/3=b/4=c/5 ⇒∆ABC is a right angle triangle

If $\vec{x}$ and $\vec{y}$ be two non-collinear vectors and a triangle $A B C$ with side lengths $a, b, c$ satisfy the vector equation
$(20 a - 15 b) \vec{x} + (15 b - 12 c) \vec{y} + (12 c - 20 a) (\vec{x} \times \vec{y}) = \vec{0}$ ,
then $∆ A B C$ is

Solution

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