Q93 / 200 · AP EAMCET 2002 · Mathematics
If $y=a e^x+b e^{-x}+c$, where $a, b, c$ are parameters, then $y^{\prime \prime \prime}$ is equal to
- A$0$
- B$y$
- Correct answerC$y^{\prime}$
- D$y^{\prime \prime}$
Solution
We have,
$$
\begin{aligned}
y & =a e^x+b e^{-x}+c \\
y^{\prime} & =a e^x-b e^{-x} \\
y^{\prime \prime} & =a e^x+b e^{-x} \\
y^{\prime \prime \prime} & =a e^x-b e^{-x}=y^{\prime}
\end{aligned}
$$
Hence, the correct answer is option: 'C'.