Q62 / 75 · JEE Main 2020 (07 Jan Shift 1) · Physics

If we need a magnification of 375 from a compound microscope of tube length 150mm and an objective of focal length 5mm, the focal length of the eye-piece, should be close to:

  • Correct answer
    A
    22mm
  • B
    2mm
  • C
    4mm
  • D
    33mm

Solution

M.P.=Lf01+Dfe;375=15051+25fe
37530=1+25fe
34530=25fe
fe=750345=2.17cm;fe≈22mm

Hence, the correct answer is option: 'A'.

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