If two points are taken on the minor axis of the ellipse (x^2)/25+(y^2)/9=1 at the same distance from the centre as the foci, then the sum of the…

Question

If two points are taken on the minor axis of the ellipse (x^2)/25+(y^2)/9=1 at the same distance from the centre as the foci, then the sum of the squares of the perpendicular distances from these points on any tangent to the ellipse is

MARKS Content Team · Accepted Answer

Correct answer: (C) 50. Given ellipse is (x^2)/25+(y^2)/9=1 … 1 e=√(1-925)=45 S0,545=S(0,4) S^(')0,-545=S^(')(0,-4) Let, the tangent to the ellipse be y=mx+√(25m^2+9) where, m is a parameter. Now, the sum of the squares of ⊥ distances on this tangent from the points S and S^(') is =m0-4+25m2+9m2+1^2+m0+4+25m2+9m2+1^2 =2/((m^2+1))4^2+(25m^2+9)=50

If two points are taken on the minor axis of the ellipse $\frac{x^{2}}{25} + \frac{y^{2}}{9} = 1$ at the same distance from the centre as the foci, then the sum of the squares of the perpendicular distances from these points on any tangent to the ellipse is

Solution

More Ellipse Questions

If two points are taken on the minor axis of the ellipse x225+y29=1 at the same distance from the centre as the foci, then the sum of the squares of the perpendicular distances from these points on any tangent to the ellipse is

Solution

More Ellipse Questions

If two points are taken on the minor axis of the ellipse $\frac{x^{2}}{25} + \frac{y^{2}}{9} = 1$ at the same distance from the centre as the foci, then the sum of the squares of the perpendicular distances from these points on any tangent to the ellipse is