Q76 / 160 · TS EAMCET 2024 (10 May Shift 1) · Mathematics
If two dice are thrown, then the probability of getting coprime numbers on the dice is
- Correct answerA$\frac{23}{36}$
- B$\frac{13}{36}$
- C$\frac{5}{6}$
- D$\frac{1}{6}$
Solution
Number of possible outcomes of event when 2 dice are thrown are $6^2=36$
Outcomes in which number are not coprimes
$\begin{aligned}
&=\{(2,2),(2,4),(2,6),(3,3),(3,6),(4,2),(4,4) \\
&(4,6),(5,5),(6,2),(6,3),(6,4),(6,6)\}
\end{aligned}$
Favourable outcomes (getting coprimes number) $=($ Total - Not coprimes number $)=36-13=23$ Required probability $=\frac{23}{36}$.
Favourable outcomes (getting coprimes number) $=($ Total - Not coprimes number $)=36-13=23$ Required probability $=\frac{23}{36}$.
Hence, the correct answer is option: 'A'.