Q78 / 180 · KCET 2015 · Mathematics
If two dice are thrown simultaneously, then the probability that the sum of the numbers which
come up on the dice to be more than \( 5 \) is
come up on the dice to be more than \( 5 \) is
- A\( \frac{5}{36} \)
- B\( \frac{1}{6} \)
- C\( \frac{5}{18} \)
- Correct answerD\( \frac{13}{18} \)
Solution
Total number of outcomes is
$6 \times 6=6$
Favourable outcomes is $(1,5),(1,6),(2,4),(2,5),(2,6),(3,3),(3,4),(3,5),(3,6),(4,2),(4,3),(4,4),(4,5),(4,6),(5,$,
$1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)$, that is 26 .
Therefore, required probability is
$P=\frac{26}{36}=\frac{13}{18}$
Hence, the correct answer is option: 'D'.