If then y=log⁡(x+√(x^2+25))/(√(x^2+25)-x) then dy/dx= …

Question

If then y=log⁡(x+√(x^2+25))/(√(x^2+25)-x) then dy/dx= ….

MARKS Content Team · Accepted Answer

Correct answer: (B) 2/(√(x^2+25)). We have, y=log⁡(x+√(x^2+25))/(√(x^2+25-x)) ⇒y=log⁡(x+x^2+25)/(2x^2+25-x^2) ⇒y=log⁡(x+x^2+25)/225 ⇒y=2log⁡x+√(x^2+25)-log25 On differentiating both sides w.r.t.x, we get dy/dx=2/(x+√(x^2+25))1+1/(2√(x^2+25))2x =2/(x+√(x^2+25))(√(x^2+25)+x)/(√(x^2+25)) =2/(√(x^2+25))

If then $y = \log [\frac{x + \sqrt{x^{2} + 25}}{\sqrt{x^{2} + 25} - x}]$ then $\frac{d y}{d x} =$ ….

Solution

Relevant Questions

If then y=log⁡x+x2+25x2+25-x then dydx= ….

Solution

Relevant Questions

If then $y = \log [\frac{x + \sqrt{x^{2} + 25}}{\sqrt{x^{2} + 25} - x}]$ then $\frac{d y}{d x} =$ ….