If $-\frac{2}{3} < x < \frac{2}{3}$, then the value of the $5^{\text {th }}$ term in the expansion of $\frac{1}{\sqrt[3]{2-3 x}}$ when $x=\frac{1}{2}$ is

• A

  $\frac{35}{256(\sqrt[3]{2})}$
• Correct answer
  B

  $\frac{35}{768(\sqrt[3]{2})}$
• C

  $\frac{7}{768(\sqrt[3]{2})}$
• D

  $\frac{105}{256(\sqrt[3]{2})}$

Hence, the correct answer is option: 'B'.