Q61 / 170 · Manipal (MET) 2016 · Mathematics

If $2 \tan ^{-1}(\cos x)=\tan ^{-1}(2 \operatorname{cosec} x)$, then the value of $x$ is

  • A
    $\frac{3 \pi}{4}$
  • Correct answer
    B
    $\frac{\pi}{4}$
  • C
    $\frac{\pi}{3}$
  • D
    None of these

Solution

$\begin{aligned} & \text { Given, } 2 \tan ^{-1}(\cos x)=\tan ^{-1}(2 \operatorname{cosec} x) \\ & \therefore \tan ^{-1}\left(\frac{2 \cos x}{1-\cos ^2 x}\right)=\tan ^{-1}(2 \operatorname{cosec} x)\end{aligned}$ $\begin{aligned} & \Rightarrow \quad \frac{2 \cos x}{1-\cos ^2 x}=2 \operatorname{cosec} x \\ & \Rightarrow \sin x=\cos x \Rightarrow x=\frac{\pi}{4}\end{aligned}$

Hence, the correct answer is option: 'B'.

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