Q61 / 170 · Manipal (MET) 2016 · Mathematics
If $2 \tan ^{-1}(\cos x)=\tan ^{-1}(2 \operatorname{cosec} x)$, then the value of $x$ is
- A$\frac{3 \pi}{4}$
- Correct answerB$\frac{\pi}{4}$
- C$\frac{\pi}{3}$
- DNone of these
Solution
$\begin{aligned} & \text { Given, } 2 \tan ^{-1}(\cos x)=\tan ^{-1}(2 \operatorname{cosec} x) \\ & \therefore \tan ^{-1}\left(\frac{2 \cos x}{1-\cos ^2 x}\right)=\tan ^{-1}(2 \operatorname{cosec} x)\end{aligned}$
$\begin{aligned} & \Rightarrow \quad \frac{2 \cos x}{1-\cos ^2 x}=2 \operatorname{cosec} x \\ & \Rightarrow \sin x=\cos x \Rightarrow x=\frac{\pi}{4}\end{aligned}$
Hence, the correct answer is option: 'B'.