If $(\sqrt{3}-\mathrm{i})^{\mathrm{n}}=2^{\mathrm{n}}, \mathrm{n} \in \mathrm{N}$, then the least possible value of n is

• A

  $3$
• B

  $4$
• C

  $6$
• Correct answer
  D

  $12$

Hence, the correct answer is option: 'D'.