Q132 / 200 · Manipal (MET) 2011 · Mathematics
If $\frac{e^x+2}{\left(e^x-1\right)\left(2 e^x-3\right)}=-\frac{3}{e^x-1}+\frac{B}{2 e^x-3}$, then $B$ is equal to
- A1
- B3
- C5
- Correct answerD7
Solution
Here, $e^x+2=-3\left(2 e^x-3\right)+B\left(e^x-1\right)$
On equating the coefficient of $e^x$ and constant, we get
$\begin{aligned} & 1=-6+B \\ & 2=9-B \Rightarrow B=7\end{aligned}$
Hence, the correct answer is option: 'D'.