Q133 / 200 · Manipal (MET) 2010 · Mathematics
If $\int f(x) d x=F(x)$, then $\int x^3 f\left(x^2\right) d x$ is equal to
- A$\frac{1}{2}\left[x^2\{F(x)\}^2-\int\{F(x)\}^2 d x\right]$
- Correct answerB$\frac{1}{2}\left[x^2 F\left(x^2\right)-\int F\left(x^2\right) d\left(x^2\right)\right]$
- C$\frac{1}{2}\left[x^2 F(x)-\frac{1}{2} \int\{F(x)\}^2 d x\right]$
- DNone of the above
Solution
We have, $\int f(x) d x=F(x)$
$\therefore \int x^3 f\left(x^2\right) d x=\frac{1}{2} \int x^2 f\left(x^2\right) d\left(x^2\right)$
$=\frac{1}{2}\left[x^2 F\left(x^2\right)-\int F\left(x^2\right) d\left(x^2\right)\right]$
Hence, the correct answer is option: 'B'.