Q85 / 180 · KCET 2013 · Mathematics
If $f(x)=\left\{\begin{array}{ll}x, & \text { if } x \text { is irrational } \\ 0, & \text { if } x \text { is rational }\end{array}\right.$, then $f$ is
- Acontinuous everywhere
- Bdiscontinuous everywhere
- Correct answerCcontinuous only at $x=0$
- Dcontinuous at all rational numbers
Solution
Given, $f(x)= \begin{cases}x, & \text { if } x \text { is irrational } \\ 0, & \text { if } x \text { is rational }\end{cases}$
$\begin{aligned}
&\mathrm{LHL}=\lim _{x \rightarrow 0^{-}} f(x)=\lim _{x \rightarrow 0^{-}} x=0 \\
&\mathrm{RHL}=\lim _{x \rightarrow 0^{+}} f(x)=\lim _{x \rightarrow 0^{+}} x=0
\end{aligned}$
and $f(0)=0$ Hence, $f(x)$ is continuous at $x=0$.
Hence, the correct answer is option: 'C'.