If $\frac{x^3+3}{(x-3)^3}=a+\frac{b}{x-3}+\frac{c}{(x-3)^2}+\frac{d}{(x-3)^3}$ then $(a+d)-(b+c)=$

• A

  $49$
• B

  $15$
• C

  $-30$
• Correct answer
  D

  $-5$

Hence, the correct answer is option: 'D'.