If $\frac{3 x^3-7 x+1}{(x-2)^5}=\frac{A}{x-2}+\frac{B}{(x-2)^2}+\frac{C}{(x-2)^3}+\frac{D}{(x-2)^4}+\frac{E}{(x-2)^5}$, then $\mathrm{A}(\mathrm{B}+\mathrm{C}+\mathrm{D}+\mathrm{E})=$

• Correct answer
  A

  $0$
• B

  $64$
• C

  $348$
• D

  $256$

Hence, the correct answer is option: 'A'.