If $\sqrt{3} \cos \theta+\sin \theta>0$ then

• A

  $-\frac{\pi}{2} < \theta < \frac{\pi}{2}$
• Correct answer
  B

  $-\frac{\pi}{3} < \theta < \frac{2 \pi}{3}$
• C

  $-\frac{2 \pi}{3} < \theta < \frac{\pi}{3}$
• D

  $-\frac{\pi}{6} < \theta < \frac{5 \pi}{6}$

Hence, the correct answer is option: 'B'.