If $\int x^2 \cos ^2 x d x=\frac{1}{6} f(x)+g(x) \sin 2 x+h(x) \cos 2 x+c$ then $\mathrm{f}(1)+\mathrm{g}(2)+\mathrm{h}\left(\frac{1}{2}\right)=$

• A

  0
• Correct answer
  B

  2
• C

  1
• D

  -1

Hence, the correct answer is option: 'B'.