Q62 / 160 · AP EAMCET 2025 (21 MAY SHIFT 2) · Mathematics
If $A+B+C=\frac{\pi}{4}$, then $\sin 4 A+\sin 4 B+\sin 4 C=$
- Correct answerA$4 \cos 2 \mathrm{~A} \cos 2 \mathrm{~B} \cos 2 \mathrm{C}$
- B$4 \sin 2 \mathrm{~A} \sin 2 \mathrm{~B} \sin 2 \mathrm{C}$
- C$1+4 \sin 2 \mathrm{~A} \sin 2 \mathrm{~B} \sin 2 \mathrm{C}$
- D$1+4 \cos 2 \mathrm{~A} \cos 2 \mathrm{~B} \cos 2 \mathrm{C}$
Hence, the correct answer is option: 'A'.