If $A=\{1,2,4\} \quad B=\{2,4,5\} \quad C=\{2,5\}$ then $(A-B) \cap(B-C)=$

Given sets $A = \{1, 2, 4\}$, $B = \{2, 4, 5\}$, and $C = \{2, 5\}$.

First, calculate $A - B$. The set $A - B$ contains elements that are in $A$ but not in $B$.
$A - B = \{1, 2, 4\} - \{2, 4, 5\} = \{1\}$.

Next, calculate $B - C$. The set $B - C$ contains elements that are in $B$ but not in $C$.
$B - C = \{2, 4, 5\} - \{2, 5\} = \{4\}$.

Finally, find the intersection $(A - B) \cap (B - C)$.
$(A - B) \cap (B - C) = \{1\} \cap \{4\} = \emptyset$.

Answer: $\emptyset$