Q112 / 170 · Manipal (MET) 2019 · Mathematics
If $n \in N$, then $|\sin n x|$
- A$\leq n|\sin x|$
- B$\geq n|\sin x|$
- C$=n|\sin x|$
- Correct answerDNone of these
Solution
$\begin{aligned} & \text { Let } \begin{aligned} T & =|\sin n x| \\ \text { Put } \quad n & =2 \text {, then } \\ T & =|\sin 2 x|=|2 \sin x \cos x| \leq 2|\sin x|\end{aligned}\end{aligned}$
Hence, the correct answer is option: 'D'.