Q88 / 200 · Manipal (MET) 2011 · Mathematics
If $Z=f(x+a y)+\phi(x-a y)$, then
- A$Z_{x x}=Z_{y y}$
- B$Z_{x x}=a^2 Z_{y y}$
- Correct answerC$Z_{y y}=a^2 Z_{x x}$
- DNone of these
Solution
Given that,
$\begin{aligned} Z & =f(x+a y)+\phi(x-a y) \\ Z_x & =f^{\prime}(x+a y)+\phi(x-a y) \\ \Rightarrow \quad Z_{x x} & =f^{\prime \prime}(x+a y)+\phi^{\prime \prime}(x-a y)\end{aligned}$
and $\quad Z_y=a f^{\prime}(x+a y)-a \phi^{\prime}(x-a y)$
$\Rightarrow \quad z_{y y}=a^2 f^{\prime \prime}(x+a y)-a^2 \phi^{\prime}(x-a y)$
Hence, $a^2 Z_{x x}=Z_{y y}$
Hence, the correct answer is option: 'C'.