Q115 / 160 · TS EAMCET 2024 (11 May Shift 1) · Mathematics
If $\int e^x\left(x^3+x^2-x+4\right) d x=e^x f(x)+c$, then $f(1)=$
- A$0$
- B$1$
- C$2$
- Correct answerD$3$
Solution
$\begin{aligned}
& \int e^x\left(x^3+x^2-x+4\right) d x=e^x f(x)+\mathrm{c} \\
\Rightarrow & e^x\left(x^3+x^2-x+4\right)=e^x f^{\prime}(x)+e^x f(x) \\
\Rightarrow & f(x)+f^{\prime}(x)=x^3+x^2-x+4
\end{aligned}$
$\begin{aligned}
& \text { Let } f(x)=x^3+a x^2+b x+c \Rightarrow f^{\prime}(x)=3 x^2+2 a x+b \\
& \Rightarrow x^3+x^2-x+4=x^3+(a+3) x^2+(2 a+b) x+b+c \\
& \Rightarrow a+3=1 \Rightarrow a=-2 \Rightarrow 2 a+b=-1 \Rightarrow b=3 \\
& b+c=4 \Rightarrow c=1 \therefore f(x)=x^3-2 x^2+3 x+1 \\
& f(1)=1-2+3+1=3
\end{aligned}$
Hence, the correct answer is option: 'D'.