If $\left[\begin{array}{ll}2 & 1 \\ 3 & 2\end{array}\right] \cdot A \cdot\left[\begin{array}{cc}-3 & 2 \\ 5 & -3\end{array}\right]=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]$, then $A=$

• Correct answer
  A

  $\left[\begin{array}{ll}1 & 1 \\ 1 & 0\end{array}\right]$
• B

  $\left[\begin{array}{ll}1 & 1 \\ 0 & 1\end{array}\right]$
• C

  $\left[\begin{array}{ll}1 & 0 \\ 1 & 1\end{array}\right]$
• D

  $\left[\begin{array}{ll}0 & 1 \\ 1 & 1\end{array}\right]$

Hence, the correct answer is option: 'A'.