Q115 / 160 · AP EAMCET 2017 (26 Apr Shift 2) · Mathematics

If $I_n=\int \frac{t^{2 n}}{1+t^2} d t$, then $I_{n+1}=$

A
$\frac{t^{2 n+1}}{2 n+1}+I_{2 n}$
B
$\frac{t^{2 n+1}}{2 n+1}+I_n$
C
$\frac{t^{2 n+1}}{2 n+1}-I_{2 n}$
Correct answer
D
$\frac{t^{2 n+1}}{2 n+1}-I_n$

Hence, the correct answer is option: 'D'.

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