Q120 / 180 · COMEDK 2019 · Mathematics
If $\int f(x) d x=g(x)$, then $\int f(x) g(x) d x=$
- A$\frac{1}{2} f^{2}(x)$
- Correct answerB$\frac{1}{2} g^{2}(x)$
- C$\frac{1}{2}\left[g^{\prime}(x)\right]^{2}$
- D$f^{\prime}(x) g(x)$
Solution
We have,
$\int f(x) d x=g(x)$
$\Rightarrow \quad f(x)=g^{\prime}(x)$
Now, let $I=\int f(x) \cdot g(x) d x=\int g^{\prime}(x) g(x) d x$
Put $g(x)=t$
$\Rightarrow \quad g^{\prime}(x) d x=d t$
$\therefore \quad I=\int t d t=\frac{t^{2}}{2}+C=\frac{1}{2}(g(x))^{2}+C$
Hence, the correct answer is option: 'B'.