Q89 / 90 · JEE Main 2024 (31 Jan Shift 1) · Physics

If the wavelength of the first member of Lyman series of hydrogen is $λ$ . The wavelength of the second member will be

Solution

For Lyman series:

For first member, $\frac{1}{λ} = \frac{13.6 Z^{2}}{h c} [\frac{1}{1^{2}} - \frac{1}{2^{2}}]$ ….. (i)

For second member, $\frac{1}{λ'} = \frac{13.6 Z^{2}}{h c} [\frac{1}{1^{2}} - \frac{1}{3^{2}}]$ ….. (ii)

On dividing (i) and (ii), we get

$λ' = \frac{27}{32} λ$

Hence, the correct answer is option: 'A'.