Q27 / 160 · TS EAMCET 2018 (05 May Shift 1) · Chemistry

If the value of $\frac{1}{n}$ is equal to 1 in Freundlich adsorption isotherm, then $\frac{x}{m}=(x=$ mass of adsorbate, $m=$ mass of the absorbent, $p=$ pressure of the gas)

  • A
    $\frac{K}{p}$
  • Correct answer
    B
    $K p$
  • C
    $K$
  • D
    0

Solution

Isothermal variation of adsorption of quantity of gas adsorbed by unit mass of solid adsorbent with pressure. This equation known as Freundlich adsorption isotherm. $$ \frac{x}{m}=K_{p^n}^{\frac{1}{n}} $$ If $$ 1 / n=1 $$ Then $$ \frac{x}{m}=K_p $$

Hence, the correct answer is option: 'B'.

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